x^2+0.05x-2,5*10^-22=0

Solution for x^2+0.05x-2,5*10^-22=0 equation:

x^2+0.05x-2.5*10^-22=0

We add all the numbers together, and all the variables

x^2+0.05x=0

a = 1; b = 0.05; c = 0;
Δ = b2-4ac
Δ = 0.052-4·1·0
Δ = 0.0025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.05)-\sqrt{0.0025}}{2*1}=\frac{-0.05-\sqrt{0.0025}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.05)+\sqrt{0.0025}}{2*1}=\frac{-0.05+\sqrt{0.0025}}{2}
$